The iodoform test is a test to determine if an organic compound is ethanol or contains a secondary alcohol (CH3—CH(OH)R). Potassium iodide and sodium hypochlorite solution are added to the organic compound in the presence of sodium hydroxide solution. Potassium hypoiodite forms, which then oxidizes the CH3—CH(OH)R group to CH3COR. Potassium hypoiodite replaces the hydrogen attached to the carbon atom adjacent to the carbonyl group with iodine. The carbon carbon bond is cleaved to give the iodoform. The iodoform is a yellow color.

The reaction is as follows:

Ethanol reacts with potassium hypoiodite to make ethanal or acetaldehyde. This then reacts with potassium hypoiodite to make C I 3 C H O. This reacts with sodium hydroxide to make iodoform, C H I 3, and sodium formate, H C O O N a.

This test can also be used to determine whether an aldehyde or ketone with the structure CH3COR is present in the organic compound. This test only works for the aldehyde ethanal. The iodoform test is a haloform reaction because a halogen in basic conditions reacts with an aldehyde or ketone.

Materials

  • Test tubes

  • Test tube rack

  • 10% potassium iodide solution

  • Sodium hypochlorite solution

  • Dioxane

  • Sodium hydroxide

  • Potassium iodine iodine reagent: prepared by dissolving 20 g of potassium iodide and 10 g of iodine in 100 mL of water.

  • Compound to be tested.

Safety

Sodium hydroxide is corrosive. Sodium hypochlorite is corrosive and an environmental hazard. Potassium iodide is harmful, a health hazard, and an environmental hazard. Dioxane is flammable, harmful, and a health hazard.

Procedure

There are 2 methods.

First method

  1. Put 0.2 mL of the compound in a test tube.

  2. Add 10 mL of 10% aqueous potassium iodide solution and 10 mL of freshly prepared sodium hypochlorite solution.

  3. Warm gently.

  4. 黄水晶的碘仿如果te分开st is positive.

Second method

  1. Dissolve 0.1 g or 4 to 5 drops of the compound in 2 mL of water. If it does not dissolve, add dioxane drop by drop to get a homogeneous solution.

  2. Add 2 mL of 5% sodium hydroxide solution followed by potassium iodide-iodine reagent dropwise with continuous shaking till a definite dark colour of iodine persists.

  3. Allow the reactants to remain at room temperature for 2-3 minutes.

  4. If no iodoform separates:

    • Warm the reaction mixture in a water bath at 60°C.
    • Add more drops of potassium iodide–iodine reagent.
    • If the colour of iodine disappears, continue addition of reagent till the colour of iodine persists even after two minutes of heating at 60°C.
    • Remove excess iodine by adding a few drops of sodium hydroxide solution with shaking.
    • Dilute the mixture with an equal volume of water and keep it at room temperature for 10-15 minutes.
  5. A yellow precipitate of the iodoform is obtained if the test is positive.


References:

  • NCERT Lab Manual for Functional Group tests
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